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A constant force of friction 50N is acting on a body of mass 200 Kg moving initially with a speed of 15 m/s. How long does the body take to
Question
A constant force of friction 50N is acting on a body of mass 200 Kg moving initially with a speed of 15 m/s. How long does the body take to stop? What distance will it cover before coming to rest?
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Physics
3 years
2021-07-17T03:37:41+00:00
2021-07-17T03:37:41+00:00 1 Answers
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Answers ( )
Answer:
F=-50N
M=200kg
U=15m/s
F=Ma
a=F/M=-50/200=-0.25
V^2-U^2=2aS
0-(15)^2=2(-0.25)S
S=-225/-0.5=450m
V=U+at
0=15-0.25t
t=-15/-0.25=60s
Explanation:
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