A constant force of friction 50N is acting on a body of mass 200 Kg moving initially with a speed of 15 m/s. How long does the body take to

A constant force of friction 50N is acting on a body of mass 200 Kg moving initially with a speed of 15 m/s. How long does the body take to stop? What distance will it cover before coming to rest?

0 thoughts on “A constant force of friction 50N is acting on a body of mass 200 Kg moving initially with a speed of 15 m/s. How long does the body take to”

  1. Answer:

    F=-50N

    M=200kg

    U=15m/s

    F=Ma

    a=F/M=-50/200=-0.25

    V^2-U^2=2aS

    0-(15)^2=2(-0.25)S

    S=-225/-0.5=450m

    V=U+at

    0=15-0.25t

    t=-15/-0.25=60s

    Explanation:

    Hope this helps, let me know if you have any questions!

    Have a great day.

    Reply

Leave a Comment