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A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At a point P th
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A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At a point P that is 1.25 cm outside the sheet, the magnitude of the electric field due to the sheet is E. If the sheet is now stretched so that its sides have length 2d, what is the magnitude of the new electric field at P? The ratio of the new magnitude of E to the initial E is
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2021-07-20T21:17:41+00:00
2021-07-20T21:17:41+00:00 1 Answers
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Answer:![Rendered by QuickLaTeX.com \frac{1}{4}](https://documen.tv/wp-content/ql-cache/quicklatex.com-83dc4a903812856a369855508d0b2637_l3.png)
Explanation:
Given
Charge Q is spread over non conducting sheet
Electric field due to sheet is![Rendered by QuickLaTeX.com E=\frac{\sigma }{2\epsilon _o}](https://documen.tv/wp-content/ql-cache/quicklatex.com-a543dee61af7ae0e4e75f76affb14d7d_l3.png)
where![Rendered by QuickLaTeX.com \sigma =\frac{charge}{area}=\frac{q}{d^2}](https://documen.tv/wp-content/ql-cache/quicklatex.com-6501a1c5a77830150d32f974df3ac681_l3.png)
Now if the sheet is stretch to becomes
length
thus the ratio of new and initial electric field is![Rendered by QuickLaTeX.com \frac{1}{4}](https://documen.tv/wp-content/ql-cache/quicklatex.com-83dc4a903812856a369855508d0b2637_l3.png)