A charge of 6.4 × 10–7 c experiences an electric force of 1.8 × 10–1 n. What is the electric field strength?

Question

A charge of 6.4 × 10–7 c experiences an electric force of 1.8 × 10–1 n. What is the electric field strength?

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Huyền Thanh 5 years 2021-07-26T10:14:51+00:00 1 Answers 29 views 0

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  1. lethu
    0
    2021-07-26T10:16:32+00:00
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    Answer:

    E=2.81\times 10^5\ N/C

    Explanation:

    Given that,

    Charge, Q=6.4\times 10^{-7}\ C

    Electric force, F=1.8\times 10^{-1}\ N

    We need to find the electric field strength. We know that due to the charge a force act on it. It is called electric force. The relation between electric force and electric field is given by :

    F=qE

    E is electric field strength

    E=\dfrac{F}{Q}\\\\E=\dfrac{1.8\times 10^{-1}}{6.4\times 10^{-7}}\\\\E=2.81\times 10^5\ N/C

    So, the electric field strength is 2.81\times 10^5\ N/C.

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