Question A certain string can withstand a maximum tension of 55N before breaking.What is the maximum speed at which we can safely swing a 1.0 kg mass on a piece of this string 0.50m long in a horizontal circle?

Explanation: Fmax = Fc = mv^2/r [tex]m \frac{ {v}^{2} }{r} = f\frac{}{max} \\ {v}^{2} = \frac{(0.50 \: m)(55 \: n)}{1.0 \: kg} = 27.5 \: \frac{ {m}^{2} }{ {s}^{2} } \\ v = 5.2 \: \frac{m}{s} [/tex] Log in to Reply

Explanation:Fmax = Fc = mv^2/r

[tex]m \frac{ {v}^{2} }{r} = f\frac{}{max} \\ {v}^{2} = \frac{(0.50 \: m)(55 \: n)}{1.0 \: kg} = 27.5 \: \frac{ {m}^{2} }{ {s}^{2} } \\ v = 5.2 \: \frac{m}{s} [/tex]