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A cell phone costs $750 and loses 28% of its value each year. What is the value of the phone after 2 years? 1. $216.54 2.
Question
A cell phone costs $750 and loses 28% of its value each year. What is the value of the phone after 2 years?
1. $216.54
2. $388.80
3. $1228.80
4. $456.30
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Mathematics
5 years
2021-08-05T04:50:15+00:00
2021-08-05T04:50:15+00:00 2 Answers
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Answers ( )
Answer:
388
Step-by-step explanation:
first year it loses 210
750×.28=210
second year phone value is 540
540×.28=151.2
third year phone value is 388
Answer:
Initial costs 750 and loses .28 of value each year, so still worth 1-.28=.72 of value at start of next year. 750*(.72)^n is the value after n years since for n=0, new, it is 750*.72^0=750*1=750, and after 1 year it is worth 750*.72^1=750*.72 means it lost 28% value after one year. If you with to express it as an exponential exp(..) you need to convert the .72^n into exp(log(.72)*n)=exp(-.3285*n) so you get
750*exp(-.3285*n) as the value after n years.