A Carnot engine operates between a high temperature reservoir at 435 K and a river with water at 280 K. If it absorbs 3700 J of heat each cy

Question

A Carnot engine operates between a high temperature reservoir at 435 K and a river with water at 280 K. If it absorbs 3700 J of heat each cycle, how much work per cycle does it perform?

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Thông Đạt 5 years 2021-08-18T04:32:43+00:00 1 Answers 134 views 0

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  1. taiduc
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    2021-08-18T04:33:51+00:00
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    Answer:

    The work done by the carnot engine per cycle is 1318.31 J

    Explanation:

    Given;

    high temperature reservoir, Th = 435 k

    temperature of river water, Tl = 280 k

    heat energy absorbed per cycle, Q = 3700 J

    Determine the work done per cycle is calculated as;

    W = Q(1-\frac{T_l}{T_h} )

    Where;

    W is the work done

    Q is the absolute heat absorbed per cycle

    Tl is the temperature of the cold liquid

    Th is the temperature of the hot reservoir

    W = Q(1-\frac{T_l}{T_h} )\\\\W = 3700(1 - \frac{280}{435} )\\\\W = 3700 (1-0.6437)\\\\W = 1318.31 \ J

    Therefore, the carnot engine operating at the given conditions, performs 1318.31 J work per cycle.

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