A car slows down from a velocity of 25 m/s to rest in 5.0 seconds. How far did the car travel during that time?

Question

A car slows down from a velocity of 25 m/s to rest in 5.0 seconds. How far did the car travel during that time?

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Thu Hương 3 years 2021-07-25T19:57:31+00:00 1 Answers 30 views 0

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  1. Xavia
    0
    2021-07-25T19:59:05+00:00
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    Answer:

    \boxed{\sf Distance \ travelled = 62.5 \ m}

    Given:

    Initial velocity (u) = 25 m/s

    Final velocity (v) = 0 m/s (Rest)

    Time taken (t) = 5 seconds

    To Find:

    Distance travelled by car (s)

    Explanation:

    From equation of motion of object moving with uniform acceleration in straight line we have:

    \boxed{ \bold{s = (\frac{v + u}{2} )t}}

    By substituting value of v, u & t in the equation we get:

    \sf \implies s = ( \frac{0 + 25}{2} ) \times 5 \\ \\ \sf \implies s = \frac{25}{2} \times 5 \\ \\ \sf \implies s = 12.5 \times 5 \\ \\ \sf \implies s = 62.5 \: m

    \therefore

    Distance travelled by car (s) = 62.5 m

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