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A bus accelerates at -0.5 m/s2 for 12.5 seconds . If the bus had an initial speed of 31 m/s, what is its new speed? A. 12.25m/s B. 37.25m/s
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Answer:
37.5m/s
Explanation:
a=(v-u)/t
0.5 = (v – 31) / 12.5
v – 31 = 0.5 x 12.5
v – 31 = 6.25
V = 6.25 + 31
v = 37.25m/s