Question A bus accelerates at -0.5 m/s2 for 12.5 seconds . If the bus had an initial speed of 31 m/s, what is its new speed? A. 12.25m/s B. 37.25m/s C. 24.75m/s D. 6.25m/s

Answer: 37.5m/s Explanation: a=(v-u)/t 0.5 = (v – 31) / 12.5 v – 31 = 0.5 x 12.5 v – 31 = 6.25 V = 6.25 + 31 v = 37.25m/s Log in to Reply

Answer:37.5m/s

Explanation:a=(v-u)/t

0.5 = (v – 31) / 12.5

v – 31 = 0.5 x 12.5

v – 31 = 6.25

V = 6.25 + 31

v = 37.25m/s