A body weighing 188N moves with a speed of 5m/s in a horizontal circular path of radius 5m. Calculate the magnitude of the centripetal force

Question

A body weighing 188N moves with a speed of 5m/s in a horizontal circular path of radius 5m. Calculate the magnitude of the centripetal force acting on the body

in progress 0
Thiên Thanh 4 years 2021-08-15T17:14:28+00:00 1 Answers 54 views 0

Answers ( )

    0
    2021-08-15T17:16:02+00:00

    The centripetal acceleration a of the body is

    a = v ² / R

    where

    • v = tangential speed of the body

    • R = radius of the circle

    Substituting these into the acceleration gives

    a = v ² / R = (5 m/s)² / (5 m)

    a = 5 m/s²

    We’re given the body’s weight W = 188 N, so its mass is m = W / g. Use Newton’s second law to get the magnitude of the centripetal force:

    F = m a = (W / g) a ≈ (188 N) / (9.80 m/s²) (5 m/s²)

    F95.9 N

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )