A body weighing 188N moves with a speed of 5m/s in a horizontal circular path of radius 5m. Calculate the magnitude of the centripetal force acting on the body

Answers

The centripetal acceleration a of the body is

a = v ² / R

where

• v = tangential speed of the body

• R = radius of the circle

Substituting these into the acceleration gives

a = v ² / R = (5 m/s)² / (5 m)

a = 5 m/s²

We’re given the body’s weight W = 188 N, so its mass is m = W / g. Use Newton’s second law to get the magnitude of the centripetal force:

F = m a = (W / g) a ≈ (188 N) / (9.80 m/s²) (5 m/s²)

The centripetal acceleration

aof the body isa=v² /Rwhere

•

v= tangential speed of the body•

R= radius of the circleSubstituting these into the acceleration gives

a=v² /R= (5 m/s)² / (5 m)a= 5 m/s²We’re given the body’s weight

W= 188 N, so its mass ism=W/g. Use Newton’s second law to get the magnitude of the centripetal force:F=m a= (W/g)a≈ (188 N) / (9.80 m/s²) (5 m/s²)F≈95.9 N