a bag contains 3 white balls and 4 red balls. A.second bag contains 4 white balls and 3 red balls. If a bag is picked at random from each ba

a bag contains 3 white balls and 4 red balls. A.second bag contains 4 white balls and 3 red balls. If a bag is picked at random from each bag. Find the probability that both are white

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  1. Answer:

    12/49 chance that they are both white

    Step-by-step explanation:

    We have 2 events going on:

    The first bag that contains: 3 white, 4 red

    The second bag that contains: 4 white, 3 red

    First let’s find the probability of picking a white ball from each individual bag (not combing the chances yet):

    For the 1st bag, there are 3 white balls out of 7 balls (add 3 and 4).

    That means there’s a 3/7 chance you’ll get a white ball from the 1st bag.

    For the 2nd bag, there are 4 white balls out of 7 balls (add 4 and 3).

    That means there’s a 4/7 chance you’ll get a white ball from the 2nd bag.

    To find the probability of getting both white from both of the bags, multiply 3/7 & 4/7:

    3/7 * 4/7 = 12/49

    You can’t simplify 12/49 further, so that’s your answer!

    Hope it helps (●’◡’●)

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