Question

A 92-kg receiver running at 8 m/s catches a pass across the middle and is immediately brought to a stop during a collision with a safety that lasts 0.6 seconds. What was the magnitude of force needed to stop the receiver

Answers

  1. Answer: 1200\ N

    Explanation:

    Given

    Mass of receiver m=92\ kg

    Running at a speed of v=8\ m/s

    time taken to stop t=0.6\ s

    We know, impulse imparted is given by

    \Rightarrow F\cdot dt=m\Delta v\\\Rightarrow F(0.6)=90(8-0)\\\\\Rightarrow F=\dfrac{90\times 8}{0.6}\\\\\Rightarrow F=1200\ N

    Thus, 1200 N is needed to stop the receiver.

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