A 700700700-Newton rightward net force is being applied to a 101010-kg object. What is the magnitude of the rightward acceleration on the object (in \text{ m}/\text{s}^2 m/s 2 start text, space, m, end text, slash, start text, s, end text, squared)

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Answer:a = 70 m/s²

Explanation:From Newton’s second law of motion, we know that when an unbalanced force is applied to an object it produces acceleration in the object in the direction of the force. Therefore,

F = maa = F/mwhere,

a = rightward acceleration = ?

F = Rightward net force = 700 N

m = Mass of Object = 10 kg

Therefore,

a = 700 N/10 kga = 70 m/s²