A 60 kg girl on a swing is pulled 1.5 meters back and then released. The girl oscillates at pi/3 radians per second.How far from equilibrium

Question

A 60 kg girl on a swing is pulled 1.5 meters back and then released. The girl oscillates at pi/3 radians per second.How far from equilibrium will the girl be in 4 seconds into the motion

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niczorrrr 5 years 2021-07-18T21:36:10+00:00 1 Answers 19 views 0

Answers ( )

  1. diemthu
    0
    2021-07-18T21:37:20+00:00
    Reply

    Answer:

    -0.75 m

    Explanation:

    The displacement of the girl is given by x = x₀cosωt where x₀ = maximum displacement of swing = 1.5 m, ω = angular frequency = π/3 rad/s and t = time of swing = 4 s

    Substituting the values of the variables into the equation, we have

    x = x₀cosωt

    x = (1.5 m)cos(π/3 rad/s × 4 s)

    x = (1.5 m)cos(2π/3)

    x = (1.5 m)cos120°

    x = 1.5 m × -0.5

    x = -0.75 m

    So, the girl is 0.75 m to the left of the equilibrium position 4 seconds into the motion.

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