Question

A 30cm long tendon was found to stretch 9.0mm by a force of 11.2N.The tendon was approximately round with an average diameter of 8.9 mm.Calculate Young’s modulus of this tendon.

Answers

  1. Answer:

    Young’s Modulus = 6 x 10⁶ Pa = 6 MPa

    Explanation:

    First we need to find the stress on tendon:

    Stress = Force/Area

    Stress = 11.2 N/πr²

    Stress = (11.2 N)/π(4.45 x 10⁻³ m)²

    Stress = 180 x 10³ Pa

    Now, we calculate the strain:

    Strain = Change in length/Original Length

    Strain = (9 x 10⁻³ m)/(0.3 m)

    Strain = 0.03

    Now, we calculate the Young’s Modulus:

    Young’s Modulus = Stress/Strain

    Young’s Modulus = (180 x 10³ Pa)/0.03

    Young’s Modulus = 6 x 10⁶ Pa = 6 MPa

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