“A 2-kg object is moving at 3 m/s. A 4-N force is applied in the direction of motion and then removed after the object has traveled an addit

Question

“A 2-kg object is moving at 3 m/s. A 4-N force is applied in the direction of motion and then removed after the object has traveled an additional 5 m. What is the work done by this force? What is the velocity of the object after the force was applied?”

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Sapo 5 years 2021-07-26T18:46:53+00:00 1 Answers 341 views 1

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  1. kiet
    0
    2021-07-26T18:48:03+00:00
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    Answer:

    Explanation:

    Given that,

    Mass m = 2kg

    Initial Velocity Vi = 3m/s

    Force applied. = 4N

    Distance cause by the force applied d = 5m

    a. Work done by the force applied?

    Work done by force applied can be determined by

    W = F×d•Cosx

    Where x is direction is the force and displacement

    The force and displacement are in the same direction, then, x =0°

    W = F×d•Cosx

    W = 4×5Cos0

    W = 20J.

    b. Final velocity

    The change in kinetic energy is equal to work done

    ∆K.E = W

    ½mVf² – ½mVi² = W

    ½mVf² = ½mVi² + W

    ½ × 2 Vf² = ½ × 2 × 3² + 20

    Vf² = 9+20

    Vf² = 29

    Vf = √29

    Vf = 5.39m/s

    The final velocity is 5.39m/s

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