A 2.0-Coulomb bead is given 20 Joules of electric potential energy by lifting it from the “ground” to point A. If a second bead with twice a

A 2.0-Coulomb bead is given 20 Joules of electric potential energy by lifting it from the “ground” to point A. If a second bead with twice as much charge, 4.0 Coulombs, is lifted through the same distance, intuitively, how much electric potential energy do you expect it to have at point A?

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  1. Answer:

    40 J

    Explanation:

    [tex]c_1[/tex] = 4 C

    [tex]c_2[/tex] = 2 C

    [tex]U_1[/tex] = 20 J

    The potential energy is directly proportional to the charge of the particle

    [tex]U\propto c[/tex]

    [tex]\dfrac{U_2}{U_1}=\dfrac{c_2}{c_1}\\\Rightarrow U_2=\dfrac{U_1c_2}{c_1}\\\Rightarrow U_2=\dfrac{20\times 4}{2}\\\Rightarrow U_2=40\ J[/tex]

    The potential energy expected is 40 J

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