A 16.0 g bullet is moving to the right with speed 250 m/s when it hits a target and travels an additional 22.6 cm into the target. What are

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A 16.0 g bullet is moving to the right with speed 250 m/s when it hits a target and travels an additional 22.6 cm into the target. What are the magnitude (in N) and direction of the stopping force acting on the bullet

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RI SƠ 5 years 2021-09-02T20:39:14+00:00 1 Answers 38 views 0

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  1. phucdien
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    2021-09-02T20:40:29+00:00
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    Answer:

    The magnitude will be “2212 N“.

    Explanation:

    The given values are:

    Initial speed, u = 250 m/s

    Final speed, v = 0

    Mass, m = 16.0 = 0.016 kg

    Distance, d = 22.6 cm

    On converting cm into m, we get

    d = 0.226 m

    As we know,

    ⇒  v^2-u^2=-2ad

    ⇒  a=\frac{v^2-u^2}{-2d}

    On putting the estimated values, we get

    ⇒    =\frac{(0)^2-(250)^2}{-2\times 0.226}

    ⇒    =\frac{0-62500}{-0.452}

    ⇒    =13,8276 \ m/s^2

    Now,

    Force, F=ma

    On putting values, we get

    ⇒            =0.016\times 138276

    ⇒            =2212 \ N (magnitude)

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