A 1200 kg car accelerates from rest to 10.0 m/s in a time of 4.50 seconds. Calculate the force that the car’s tires exerted on the road.

Question

A 1200 kg car accelerates from rest to 10.0 m/s in a time of 4.50 seconds. Calculate the force that the car’s tires exerted on the road.
please help me i need the answer in 10 mins

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Ngọc Hoa 5 years 2021-08-18T13:05:46+00:00 1 Answers 210 views 0

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  1. kimchi2
    0
    2021-08-18T13:07:08+00:00
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    Answer:

    the force that the car’s tires exerted on the road is 2,666.67 N.

    Explanation:

    Given;

    mass of the car, m = 1,200 kg

    initial velocity of the car, u = 0

    final velocity of the car, v =  10.0 m/s

    time of motion, t = 4.50 s

    The force the car’s tires exerted on the road is calculated as follows;

    F = ma= \frac{m(v-u)}{t} \\\\F = \frac{1200(10-0)}{4.5} \\\\F = 2,666.67 \ N

    Therefore, the force that the car’s tires exerted on the road is 2,666.67 N.

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