A 100-watt light bulb radiates energy at a rate of 100 J/s. (The watt, a unit of power or energy over time, is defined as 1 J/s.) If all of

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A 100-watt light bulb radiates energy at a rate of 100 J/s. (The watt, a unit of power or energy over time, is defined as 1 J/s.) If all of the light emitted has a wavelength of 525nm, how many photons are emitted per second?

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Thành Công 5 years 2021-08-18T12:37:08+00:00 1 Answers 50 views 0

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  1. bonexptip
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    2021-08-18T12:38:09+00:00
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    Answer:

    2.64\times 10^{20} photons are emitted per second.

    Explanation:

    Let the number of photons emitted by bulb be ‘n’.

    Given:

    Energy radiated by bulb per second (E) = 100 J

    Wavelength of light emitted (λ) = 525 nm = 525\times 10^{-9}\ m

    We know that,

    Energy of a photon is given as:

    E_0=\frac{hc}{\lambda}

    Where,

    h\to Planck's\ constant=6.626\times 10^{-34}\ Js\\\\c\to Speed\ of \ light=3\times 10^{8}\ m/s

    Now, if there are ‘n’ photons, the energy will be equal to energy of 1 photon times the number of photons. So,

    E=nE_0\\\\E=\frac{nhc}{\lambda}

    Now, rewriting in terms of ‘n’, we get:

    n=\frac{E\lambda}{hc}

    Plug in the values given and solve for ‘n’. This gives,

    n=\frac{100\times 525\times 10^{-9}}{6.626\times 10^{-34}\times 3\times 10^{8}}\\\\n=2.64\times 10^{20}

    Therefore, 2.64\times 10^{20} photons are emitted per second.

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