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2sin 2A – sin 4A 2sin 2A + sin 4A = tan²A
Question
2sin 2A – sin 4A
2sin 2A + sin 4A
= tan²A
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Mathematics
4 years
2021-09-03T18:17:53+00:00
2021-09-03T18:17:53+00:00 1 Answers
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Answers ( )
Answer:
tan²A – sin²A = tan² A sin²A
from LHS,
tan²A -sin²A
= (sin²A / cos²A) – sin²A……[tan A=sin A/cos A]
= (sin²A – sin²Acos²A) / cos²A
= sin²A (1- cos²A) / cos² A [tan A = sinA / cos A]
= tan²A sin²A= RHS
.•. hence proved
Step-by-step explanation:
Hope it is helpful…