3 years ago, Nancy’s age was more than Khaled’s age by 2, 4 years from now, twice Nancy’s age will be more than Khaled’s age by 16. Find the

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3 years ago, Nancy’s age was more than Khaled’s age by 2, 4 years from now, twice Nancy’s age will be more than Khaled’s age by 16. Find their ages.

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Ben Gia 5 years 2021-08-22T03:50:37+00:00 1 Answers 14 views 0

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    2021-08-22T03:52:27+00:00

    Answer:

    Nancy’s age is 11years and Khaled’s age is 10years

    Step-by-step explanation:

    Let Nancy’s present age be x

    Let Khaled’s present age b y

    3 years ago

    Nancy = x – 3

    Khaled = y – 3

    If 3 years ago, Nancy’s age was more than Khaled’s age by 2, then;

    x-3 = y-3 + 2

    x – 3 = y – 1

    x- y = -1+3

    x –  y = 2 …1

    4 years from now,

    Nancy = x+4

    Khaled = y+4

    If by 4years from now, twice Nancy’s age will be more than Khaled’s age by 16, then;

    2(x+4) = y+4 + 16

    2x+8 = y+20

    2x-y = 20-8

    2x-y = 12 ….2

    Subtract 1 from 2;

    x – 2x = 1 – 12

    -x = -11

    x = 11

    Since x – y = 1

    11 – y = 1

    y = 11-1

    y = 10

    Hence Nancy’s age is 11years and Khaled’s age is 10years

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )