(x+1)^2=4×(x^2-2x+1)

Question

(x+1)^2=4×(x^2-2x+1)

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Mộc Miên 5 years 2021-05-03T14:40:21+00:00 2 Answers 16 views 0

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  1. thachthao
    0
    2021-05-03T14:41:52+00:00
    Reply

    Đáp án: `S={1/3;3}`

     

    Giải thích các bước giải:

          `(x+1)² =4(x²-2x+1)`

    `<=>x² +2x+1 =4x² -8x +4`

    `<=> 4x² -x² -8x -2x+4-1=0`

    `<=> 3x² -10x+3=0`

    `<=> (x-1/3)(x-3)=0`

    `<=>`\(\left[ \begin{array}{l}x-\dfrac{1}{3}=0\\x-3=0\end{array} \right.\) 

    `<=>`\(\left[ \begin{array}{l}x=\dfrac{1}{3}\\x=3\end{array} \right.\) 

    Vậy `S={1/3;3}`

  2. mit
    0
    2021-05-03T14:42:09+00:00
    Reply

    `(x+1)^2=4(x^2-2x+1)`
    `<=>x^2+2x+1=4x^2-8x+4`
    `<=>x^2+2x+1-4x^2+8x-4=0`
    `<=>−3x^2+10x-3=0`
    `<=>−(3x−1)(x−3)=0`
    `<=>`\(\left[ \begin{array}{l}−3x+1=0\\x-3=0\end{array} \right.\)

    `<=>`\(\left[ \begin{array}{l}−3x=-1\\x=3\end{array} \right.\)

    `<=>`\(\left[ \begin{array}{l}x=\dfrac13\\x=3\end{array} \right.\)    

    Vậy `S={1/3;3}`

    $#Blink$ $\boxed{\text{@Rosé}}$

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )