Đáp án: `S={1/3;3}` Giải thích các bước giải: `(x+1)² =4(x²-2x+1)` `<=>x² +2x+1 =4x² -8x +4` `<=> 4x² -x² -8x -2x+4-1=0` `<=> 3x² -10x+3=0` `<=> (x-1/3)(x-3)=0` `<=>`\(\left[ \begin{array}{l}x-\dfrac{1}{3}=0\\x-3=0\end{array} \right.\) `<=>`\(\left[ \begin{array}{l}x=\dfrac{1}{3}\\x=3\end{array} \right.\) Vậy `S={1/3;3}` Log in to Reply
`(x+1)^2=4(x^2-2x+1)``<=>x^2+2x+1=4x^2-8x+4``<=>x^2+2x+1-4x^2+8x-4=0``<=>−3x^2+10x-3=0``<=>−(3x−1)(x−3)=0``<=>`\(\left[ \begin{array}{l}−3x+1=0\\x-3=0\end{array} \right.\) `<=>`\(\left[ \begin{array}{l}−3x=-1\\x=3\end{array} \right.\) `<=>`\(\left[ \begin{array}{l}x=\dfrac13\\x=3\end{array} \right.\) Vậy `S={1/3;3}` $#Blink$ $\boxed{\text{@Rosé}}$ Log in to Reply
Đáp án: `S={1/3;3}`
Giải thích các bước giải:
`(x+1)² =4(x²-2x+1)`
`<=>x² +2x+1 =4x² -8x +4`
`<=> 4x² -x² -8x -2x+4-1=0`
`<=> 3x² -10x+3=0`
`<=> (x-1/3)(x-3)=0`
`<=>`\(\left[ \begin{array}{l}x-\dfrac{1}{3}=0\\x-3=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\dfrac{1}{3}\\x=3\end{array} \right.\)
Vậy `S={1/3;3}`
`(x+1)^2=4(x^2-2x+1)`
`<=>x^2+2x+1=4x^2-8x+4`
`<=>x^2+2x+1-4x^2+8x-4=0`
`<=>−3x^2+10x-3=0`
`<=>−(3x−1)(x−3)=0`
`<=>`\(\left[ \begin{array}{l}−3x+1=0\\x-3=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}−3x=-1\\x=3\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\dfrac13\\x=3\end{array} \right.\)
Vậy `S={1/3;3}`
$#Blink$ $\boxed{\text{@Rosé}}$