Share
In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.
Question
In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.
in progress
0
Mathematics
5 years
2021-08-26T02:49:48+00:00
2021-08-26T02:49:48+00:00 1 Answers
46 views
0
Answers ( )
Answer:
90,597 square inches
Step-by-step explanation:
In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.
We solve using Heron’s formula
A = √s(s -a)(s – b) (s – c)
s = a + b + c/2
a = 410 inches
b = 530 inches
c = 830 inches
Hence,
s = 410 + 530 + 830/2
s = 885
A = √885(885 – 410)(885 – 530)(885 – 830)
A = 90,597.030166557 square inches
Approximately = 90,597.0 square inches