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The root for an equation x²-px+6=0 ls 3. Find the value of p Jawapan / Anne IP
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The root for an equation x²-px+6=0 ls 3. Find the value of p
Jawapan / Anne
IP
in progress
0
Mathematics
5 years
2021-09-01T11:08:19+00:00
2021-09-01T11:08:19+00:00 1 Answers
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Answers ( )
Answer:
5
Step-by-step explanation:
Given that 3 is a root of the equation x²-px+6=0
To find the value of p, substitute 3 into the equation for x
Hence x²-px+6=0
becomes
3^2 – 3p + 6 = 0
9 -3p + 6 = 0
collect like terms
-3p = -9 – 6
-3p = -15
Divide both sides by -3
p = -15/-3
p = 5