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If a projectile is fired with an initial velocity of V meters per second at an angle A above the horizontal and air resistance is assumed to
Question
If a projectile is fired with an initial velocity of V meters per second at an angle A above the horizontal and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equations
x=(Vcos(A))t,
y=(Vsin(A))t−12gt2,
A gun is fired with a = 30° and v0 = 500 m/s. When will the bullet hit the ground?
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Physics
3 years
2021-07-22T13:16:47+00:00
2021-07-22T13:16:47+00:00 1 Answers
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Answers ( )
Answer:
The projectile will hit the ground after about 1min 41 seconds
T=100.7 seconds
Explanation:
The time of flight for a projectile motion is expressed as
T=(2usin0)/g
Where u is the initial velocity
Theta 0 is the projected angle
Assuming g=9.81m/s
Given data
Theta 0= 30°
u =500m/s
Substituting our data into the expression we have
T=(2*500*sin30°)/9.81
T=(1000*−0.988)/9.81
T=988/9.81
T=100.7 second
The projectile will hit the ground after about 1min 41 seconds