What average force is required to stop a 1400 kg car in 8.0 s if the car is traveling at 95 km/h?

Question

What average force is required to stop a 1400 kg car in 8.0 s if the car is traveling at 95 km/h?

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Nick 5 years 2021-07-16T12:53:57+00:00 1 Answers 21 views 0

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  1. Nem
    0
    2021-07-16T12:55:56+00:00
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    Answer: -424.24 N

    It’s negative because the vehicle is in motion and we want to bring it to a full stop, therefore we must apply a force in the opposite direction.

    Explanation:

    F = ma\\\\F = Force\\m = mass (kg)\\a = acceleration (m/s^2)

    Find the acceleration

    V_1 = 95km/h\\V_2 = 0

    Convert from km/h to m/s

    95\frac{km}{h} (\frac{1000m}{1km} )(\frac{1h}{3600s} )= 26.39m/s

    a = \frac{V_2-V_1}{t}\\\\a = \frac{0-26.39m/s }{8s}\\\\a = -3.30m/s^2

    Plug this information into the original Force Formula

    F =ma\\\\F = (1400kg)(-3.30m/s^2)\\F =-424.24 N

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