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3.7.6. A satellite is in a circular orbit around the Earth. If it is at an altitude equal to twice the radius of the Earth, 2RE, how does it
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3.7.6. A satellite is in a circular orbit around the Earth. If it is at an altitude equal to twice the radius of the Earth, 2RE, how does its speed v relate to the Earth’s radius RE, and the magnitude g of the acceleration due to gravity on the Earth’s surface?a)b)c)d)e)
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Physics
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2021-07-18T23:13:10+00:00
2021-07-18T23:13:10+00:00 1 Answers
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Answer:
Explanation:
For acceleration due to gravity
g = GM / R² —————————- ( 1 )
At height 2R , radius of orbit is 3R .
If speed of satellite be v
m v² / 3R = GMm / (3R)² ( centripetal force = gravitational force )
v² = GM / 3R ————————————– ( 2 )
Dividing (1) and (2)
v² / g = R / 3
v² = gR / 3
v = √( gR / 3 )