The Earth’s electric field creates a potential that increases 100 V for every meter of altitude. If an object of charge 4.5 mC and mass 68

Question

The Earth’s electric field creates a potential that increases 100 V for every meter of altitude. If an object of charge 4.5 mC and mass 68 g falls a distance of 1.0 m from rest under the influence of the Earth’s electric and gravitational fields, what is its final kinetic energy

in progress 0
Edana Edana 5 years 2021-08-29T04:03:25+00:00 1 Answers 21 views 0

Answers ( )

  1. kimcuc
    0
    2021-08-29T04:05:11+00:00
    Reply

    Answer:

    The final kinetic energy is  K = 1.1 \ J

    Explanation:

    From the question we are told that

        The electric field is  E = 100 \ V/m

        The charge on the object is  q = 4.5 mC = 4.5 *10^{-3} \ C

        The mass of the object is  m_o = 68 \ g = 0.68 \ kg

         The distance moved by the object is d = 1.0 \ m

    The workdone on the object by the fields  is  mathematically represented as

       W = [qE + mg]d

    Now this workdone is equivalent to the final kinetic energy so  

          K = W = [qE + mg]d

    substituting values

            K = W = [4.5*10^{-3 } *100 + 0.68 * 9.8]* 1

            K = 1.1 \ J

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )