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A train accelerates at -1.5 m/s2 for 10 seconds. If the train had an initial speed of 32 m/s, what is its new speed? A. 17 m/s
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Answers ( )
Answer:
17 m/s
Explanation:
Using formula a = (v-u) /t
acceleration a = -1.5 m/s2
final velocity v = unknown
initial velocity u = 32 m/s
time t = 10s
-1.5 = (v-32)/10
-15 = v – 32
-15 + 32 = v
v = 17 m/s