Question A train accelerates at -1.5 m/s2 for 10 seconds. If the train had an initial speed of 32 m/s, what is its new speed? A. 17 m/s B. 15 m/s C. 47 m/s D. 32 m/s

Answer: 17 m/s Explanation: Using formula a = (v-u) /t acceleration a = -1.5 m/s2 final velocity v = unknown initial velocity u = 32 m/s time t = 10s -1.5 = (v-32)/10 -15 = v – 32 -15 + 32 = v v = 17 m/s Log in to Reply

Answer:17 m/s

Explanation:Using formula a = (v-u) /t

acceleration a = -1.5 m/s2

final velocity v = unknown

initial velocity u = 32 m/s

time t = 10s

-1.5 = (v-32)/10

-15 = v – 32

-15 + 32 = v

v = 17 m/s