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A sprinter is running a 100m sprint race. The race begins, and stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and pass
Question
A sprinter is running a 100m sprint race. The race begins, and stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and passes the 59m [N] mark at 7.98s, What was the sprinter’s average velocity between the two time marks? Show all your work.
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Physics
3 years
2021-08-07T01:04:16+00:00
2021-08-07T01:04:16+00:00 1 Answers
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Answers ( )
Answer:
velocity = 7.7558 m/s
Explanation:
s = u × t
s – distance u – velocity t – time
59 – 12 = (7.98 – 1.92) *u
47 = ( 6.06) u
u = 7.7558 m/s