b) The spring stretches from 10 cm to 22 cm when a force of 4 N is applied. If it obeys Hooke’s law, find the total length in cm when

Question

b) The spring stretches from 10 cm to 22 cm when a force of 4 N is applied. If it obeys
Hooke’s law, find the total length in cm when a force of 6 N is applied to it. [3]?

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Ngọc Hoa 4 years 2021-08-02T16:12:37+00:00 1 Answers 444 views 0

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  1. thanhha
    0
    2021-08-02T16:13:48+00:00
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    Answer:

    The intial length of the spring when on force was applied = 10 cm

    Final length of spring when force applies to the suspended spring = 22cm

    Total distance covered by the spring = (22-10)cm = 12 cm

    Magnitude of force when applied = 4N

    as we can write that 4N = 12cm

    SO,1N = (12/4) cm = 3cm

    so 6N of force does (6×3) cm= 18cm(ans)

    Hope it helps

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