b) The spring stretches from 10 cm to 22 cm when a force of 4 N is applied. If it obeys
Hooke’s law, find the total length in cm when a force of 6 N is applied to it. [3]?
b) The spring stretches from 10 cm to 22 cm when a force of 4 N is applied. If it obeys
Hooke’s law, find the total length in cm when a force of 6 N is applied to it. [3]?
Answer:
The intial length of the spring when on force was applied = 10 cm
Final length of spring when force applies to the suspended spring = 22cm
Total distance covered by the spring = (22-10)cm = 12 cm
Magnitude of force when applied = 4N
as we can write that 4N = 12cm
SO,1N = (12/4) cm = 3cm
so 6N of force does (6×3) cm= 18cm(ans)
Hope it helps