Calculate the temperature of a gas when it is expanded to 5.25L. The gas originally occupies 3.90L of space at 252K.

Question

Calculate the temperature of a gas when it is expanded to 5.25L. The gas originally occupies 3.90L of space at 252K.

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niczorrrr 4 years 2021-09-03T15:05:34+00:00 1 Answers 31 views 0

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  1. Maris
    0
    2021-09-03T15:06:40+00:00
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    Answer:

    T_2=339K

    Explanation:

    Hello there!

    In this case, according to the Charles’ gas law as way to understand the volume-temperature as a directly proportional relationship for this problem, we can write:

    \frac{T_2}{V_2}=\frac{T_1}{V_1}

    Thus, given the initial temperature and volume and the final volume, we are able to calculate the final temperature as follows:

    T_2=\frac{T_1V_2}{V_1} \\\\T_2=\frac{252K*5.25L}{3.90L}\\\\T_2=339K

    Best regards!

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