Calculate the temperature of a gas when it is expanded to 5.25L. The gas originally occupies 3.90L of space at 252K.

Answer:

[tex]T_2=339K[/tex]

Explanation:

Hello there!

In this case, according to the Charles’ gas law as way to understand the volume-temperature as a directly proportional relationship for this problem, we can write:

[tex]\frac{T_2}{V_2}=\frac{T_1}{V_1}[/tex]

Thus, given the initial temperature and volume and the final volume, we are able to calculate the final temperature as follows:

Answer:[tex]T_2=339K[/tex]

Explanation:Hello there!

In this case, according to the Charles’ gas law as way to understand the volume-temperature as a directly proportional relationship for this problem, we can write:

[tex]\frac{T_2}{V_2}=\frac{T_1}{V_1}[/tex]

Thus, given the initial temperature and volume and the final volume, we are able to calculate the final temperature as follows:

[tex]T_2=\frac{T_1V_2}{V_1} \\\\T_2=\frac{252K*5.25L}{3.90L}\\\\T_2=339K[/tex]

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