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Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:
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The question is incomplete, the complete question is:
Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:
(a): Calculate the grams of in 10.58 L of nitrogen gas
(b): Calculate the grams of in moles of nitrogen gas
(c): Calculate the moles of molecules in 3.94 grams of nitrogen gas
(d): Calculate the moles of molecules in 4.73 L of nitrogen gas
Answer: The correct options are (b) and (c).
Explanation:
We are given:
Molar mass of = 28.02 g/mol
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
At STP conditions:
1 mole of gas occupies 22.4 L of volume
For the given options:
(a): Volume is given and to calculate the mass of , we need to use both the conversion factors above.
The equation formed will be:
Mass of =
(b): Moles are given and to calculate the mass of , we need only the first conversion factor.
The equation formed will be:
Mass of =
(c): Mass is given and to calculate the moles of molecules, we need only the first conversion factor.
The equation formed will be:
Moles of molecules =
(d): Volume is given and to calculate the moles of molecules, we need only the second conversion factor.
The equation formed will be:
Moles of molecules =
Hence, the correct option is (b) and (c)