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Calcium-41 is being used in studies testing the effectiveness of drugs for preventing osteoporosis. The half-life of calcium-41 is 100
Question
Calcium-41 is being used in studies testing the effectiveness of drugs for preventing osteoporosis. The half-life of calcium-41 is 100,000 years. If 20 grams of calcium-41 are present initially, how long would it take until only 2 grams
remains?
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Mathematics
3 years
2021-08-26T01:09:00+00:00
2021-08-26T01:09:00+00:00 1 Answers
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Answers ( )
Answer:
332,193 years
Step-by-step explanation:
From the question above, we are to calculate the time in an half life question, hence, the formula is given as
t = In(Nt/No) ÷ -(In2/t½)
Where
t = time is takes for an substance to decay or reduce
Nt = Amount of sample after time = 2g
No = Initial amount of sample = 20g
t½ = Half life = 100,000 years
Hence,
t = In(2/20) ÷ (In 2/ 100,000)
t = 332192.80948874 years
Approximately = 332,193 years