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One number is six more than another number. The sum of their squares is 90.
Question
One number is six more than another number. The sum of their squares is 90.
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Mathematics
3 years
2021-07-20T04:50:17+00:00
2021-07-20T04:50:17+00:00 1 Answers
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Answers ( )
First number: x
Second: x + 6
(x)^2 + (x + 6)^2 = 90
x^2 + x^2 + 6x + 6x + 36 = 90
Simplify more
2x^2 + 12x + 36 = 90
2x^2 + 12x – 54 = 0
2(x + 9)(x – 3) = 0
You know that x = -9, and 3
The first number is 3, the other -9