9. Write the equation of a line that is PERPENDICULAR to 6x+3y=15 and passes through the coordinate (12,-5).

Question

9. Write the equation of a line that is PERPENDICULAR to 6x+3y=15 and passes
through the coordinate (12,-5).

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Farah 4 years 2021-08-22T05:42:02+00:00 1 Answers 21 views 0

Answers ( )

  1. Acacia
    0
    2021-08-22T05:43:47+00:00
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    Answer:

    y = 1/2x – 11

    Step-by-step explanation:

    Step one convert to y = mx+b form

    6x + 3y =15

    Isolate Y

    3y = -6x + 15

    Divde the 3 among the other numbers

    y = -2x + 5

    That is the equation

    perpindiculr to that is y = 1/2x + 5 but solve for the points and plug in

    the points are (12,-5)

    So -5 = 1/2 (12) +b

    -5 =  6 + b

    Solve for B

    -5 – 6 = b

    b = -11

    FINAL EQUATION

    y = 1/2x – 11

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