Question 9. Write the equation of a line that is PERPENDICULAR to 6x+3y=15 and passes through the coordinate (12,-5).

Answer: y = 1/2x – 11 Step-by-step explanation: Step one convert to y = mx+b form 6x + 3y =15 Isolate Y 3y = -6x + 15 Divde the 3 among the other numbers y = -2x + 5 That is the equation perpindiculr to that is y = 1/2x + 5 but solve for the points and plug in the points are (12,-5) So -5 = 1/2 (12) +b -5 = 6 + b Solve for B -5 – 6 = b b = -11 FINAL EQUATION y = 1/2x – 11 Log in to Reply

Answer:y = 1/2x – 11

Step-by-step explanation:Step one convert to y = mx+b form

6x + 3y =15

Isolate Y

3y = -6x + 15

Divde the 3 among the other numbers

y = -2x + 5

That is the equation

perpindiculr to that is y = 1/2x + 5 but solve for the points and plug in

the points are (12,-5)

So -5 = 1/2 (12) +b

-5 = 6 + b

Solve for B

-5 – 6 = b

b = -11

FINAL EQUATION

y = 1/2x – 11