60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop​

Question

60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop​

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Sigridomena 3 years 2021-08-24T23:31:29+00:00 2 Answers 3 views 0

Answers ( )

  1. Orla
    0
    2021-08-24T23:32:36+00:00
    Reply

    Answer:

    0.25\ cm^3

    Explanation:

    Data provided in the question

    Number of drops fell from a burret = 60

    The first reading is 28 cm^3

    And, the final reading is 43 cm^3

    Based on the above information, the average volume of one drop is

    = \frac{Final\ readings - first\ readings}{number\ of\ drops}

    = \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}

    = 0.25\ cm^3

    Basically we applies the above formula by applying the three items given in the question so that the average volume of one drop could come

  2. haidang
    0
    2021-08-24T23:33:16+00:00
    Reply

    Answer:

    0.25\ cm^30.25 cm

    3

    Explanation:

    Data provided in the question

    Number of drops fell from a burret = 60

    The first reading is 28 cm^3

    And, the final reading is 43 cm^3

    Based on the above information, the average volume of one drop is

    = \frac{Final\ readings – first\ readings}{number\ of\ drops}=

    number of drops

    Final readings−first readings

    = \frac{43\ cm^3 – 28\ cm^3}{60 \ drops}=

    60 drops

    43 cm

    3

    −28 cm

    3

    = 0.25\ cm^3=0.25 cm

    3

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