60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop
Question
Question
60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop
Answer:
[tex]0.25\ cm^3[/tex]
Explanation:
Data provided in the question
Number of drops fell from a burret = 60
The first reading is 28 cm^3
And, the final reading is 43 cm^3
Based on the above information, the average volume of one drop is
[tex]= \frac{Final\ readings – first\ readings}{number\ of\ drops}[/tex]
[tex]= \frac{43\ cm^3 – 28\ cm^3}{60 \ drops}[/tex]
[tex]= 0.25\ cm^3[/tex]
Basically we applies the above formula by applying the three items given in the question so that the average volume of one drop could come
Answer:
0.25\ cm^30.25 cm
3
Explanation:
Data provided in the question
Number of drops fell from a burret = 60
The first reading is 28 cm^3
And, the final reading is 43 cm^3
Based on the above information, the average volume of one drop is
= \frac{Final\ readings – first\ readings}{number\ of\ drops}=
number of drops
Final readings−first readings
= \frac{43\ cm^3 – 28\ cm^3}{60 \ drops}=
60 drops
43 cm
3
−28 cm
3
= 0.25\ cm^3=0.25 cm
3