Question 60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop

Answer: [tex]0.25\ cm^3[/tex] Explanation: Data provided in the question Number of drops fell from a burret = 60 The first reading is 28 cm^3 And, the final reading is 43 cm^3 Based on the above information, the average volume of one drop is [tex]= \frac{Final\ readings – first\ readings}{number\ of\ drops}[/tex] [tex]= \frac{43\ cm^3 – 28\ cm^3}{60 \ drops}[/tex] [tex]= 0.25\ cm^3[/tex] Basically we applies the above formula by applying the three items given in the question so that the average volume of one drop could come Log in to Reply

Answer: 0.25\ cm^30.25 cm 3 Explanation: Data provided in the question Number of drops fell from a burret = 60 The first reading is 28 cm^3 And, the final reading is 43 cm^3 Based on the above information, the average volume of one drop is = \frac{Final\ readings – first\ readings}{number\ of\ drops}= number of drops Final readings−first readings = \frac{43\ cm^3 – 28\ cm^3}{60 \ drops}= 60 drops 43 cm 3 −28 cm 3 = 0.25\ cm^3=0.25 cm 3 Log in to Reply

Answer:[tex]0.25\ cm^3[/tex]

Explanation:Data provided in the question

Number of drops fell from a burret = 60

The first reading is 28 cm^3

And, the final reading is 43 cm^3

Based on the above information, the average volume of one drop is

[tex]= \frac{Final\ readings – first\ readings}{number\ of\ drops}[/tex]

[tex]= \frac{43\ cm^3 – 28\ cm^3}{60 \ drops}[/tex]

[tex]= 0.25\ cm^3[/tex]

Basically we applies the above formula by applying the three items given in the question so that the average volume of one drop could come

Answer:0.25\ cm^30.25 cm

3

Explanation:Data provided in the question

Number of drops fell from a burret = 60

The first reading is 28 cm^3

And, the final reading is 43 cm^3

Based on the above information, the average volume of one drop is

= \frac{Final\ readings – first\ readings}{number\ of\ drops}=

number of drops

Final readings−first readings

= \frac{43\ cm^3 – 28\ cm^3}{60 \ drops}=

60 drops

43 cm

3

−28 cm

3

= 0.25\ cm^3=0.25 cm

3