3. Adrian is 8 years older than his brother, Jose. In 3 years he will be twice as old as his brother. Find the present age of each.​

Question

3. Adrian is 8 years older than his brother, Jose. In 3 years he will be twice as old as his brother. Find the present age of each.​

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Sigridomena 5 years 2021-09-03T10:28:10+00:00 1 Answers 17 views 0

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  1. Farah
    0
    2021-09-03T10:30:02+00:00
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    Answer:

    Age of Jose =  5 years

    Age of Adrian = 13 years

    Step-by-step explanation:

    Let:

    Age of Jose = x

    Age of Adrian = x+8

    After 3 years

    Age of Jose = x+3

    Age of Adrian = x+8+3 = x+11

    Now, we are given, in 3 years he will be twice as old as his brother.

    So, we can write

    Age of Adrian = 2 (Age of Jose)

    x+11 = 2(x+3)

    x+11=2x+6

    2x-x=11-6

    x=5

    So, we get value of x = 5

    Now, the present ages will be:

    Age of Jose = x = 5 years

    Age of Adrian = x+8 = 5+8 = 13 years

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