3.3 mol Fe(OH)3 and 6.3 mole H2SO4react according to the equation 2Fe(OH)3 + 3H2SO4 → Fe2(SO4)3 + 6H2O. If the limiting reactant is F

Question

3.3 mol Fe(OH)3 and 6.3 mole H2SO4react according to the equation 2Fe(OH)3 + 3H2SO4 → Fe2(SO4)3 + 6H2O.
If the limiting reactant is Fe(OH)3, determine the amount of excess reactant that remains. Answer in units of mol.

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Jezebel 5 years 2021-07-10T12:17:28+00:00 1 Answers 31 views 0

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  1. thnahdat
    0
    2021-07-10T12:19:24+00:00
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    Answer and Explanation:

    2 mol of Fe(OH)3 produces 1 mol of Fe2(SO4)3  then 2.1 mol of Fe(OH)3 will produce (1)/(2) x 2.01 = 1.05 mol of Fe2(SO4)3  amount of H2O = (6)/(2) * 2.01 = 6.03 mol HO2

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