10ax – 5ax – 5ay + 2x – y = ( 10ax -5ax ) – ( 5ay + y ) + 2x = (5ax +2x) – ( 5ay + y ) = x(5a + 2)- y(5a – y) Đề như này mới ra nha Reply

10ax – 5ax – 5ay + 2x – y

= ( 10ax -5ax ) – ( 5ay + y ) + 2x

= (5ax +2x) – ( 5ay + y )

= x(5a + 2)- y(5a – y)

Đề như này mới ra nha

=))

`10ax – 5ax – 5ay + 2x – y`

`= (5ax +2x) – ( 5ay + y )`

`= x(5a + 2)- y(5a – y)`