X+1/(-2)^2 = 4/x+1 Tìm x

Question

X+1/(-2)^2 = 4/x+1
Tìm x

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Khoii Minh 4 years 2020-10-29T23:46:48+00:00 2 Answers 52 views 0

Answers ( )

  1. Dulcie
    0
    2020-10-29T23:48:09+00:00
    Reply

    $\dfrac{x+1}{(-2)^2}=\dfrac{4}{x+1}$ (ĐK: $x+1\ne 0$)

    $↔\dfrac{x+1}{4}=\dfrac{4}{x+1}$

    TH1: 

    $↔(x+1)^2=4^2$

    $↔x+1=4$

    $↔x=3$

    TH2:

    $↔(x+2)^2=(-4)^2$

    $↔x+2=-4$

    $↔x=-6$

    Vậy $x=3,-6$

  2. kiet
    0
    2020-10-29T23:48:39+00:00
    Reply

    Đáp án:

    $\text{x = 3 hoặc x = -5.}$

    Giải thích các bước giải:

    `(x+1)/(-2)^2 = 4/(x+1).`

    `⇒(x+1).(x+1)= 4.(-2)^2.`

    `⇒(x+1)^2= 4^2=(-4)^2.`

    $\text{* Trường hợp 1:}$

    $\text{x + 1 = 4.}$

    $\text{⇒ x = 4 – 1.}$

    $\text{⇒ x = 3.}$

    $\text{* Trường hợp 2:}$

    $\text{x + 1 = -4.}$

    $\text{⇒ x = -4 – 1.}$

    $\text{⇒ x = -5.}$

    $\text{Vậy x = 3 hoặc x = -5.}$

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )