x+1 = (x+1)^2 Tìm x

Question

x+1 = (x+1)^2
Tìm x

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Philomena 4 years 2020-10-16T15:30:53+00:00 2 Answers 79 views 0

Answers ( )

  1. Adela
    0
    2020-10-16T15:32:09+00:00
    Reply

    Đáp án:

     

    Giải thích các bước giải:

    x+1 = (x+1)^2   

    <=>x+1=x^2+2x+1

    <=>1-1=x^2+2x-x

    <=>0=x^2+x

    <=>0=x(x+1)

    <=>x=0 hoặc x+1=0

    <=>x=0  hoặc x=-1

    Vậy x={0;-1}

     

  2. King
    0
    2020-10-16T15:32:11+00:00
    Reply

    $x+1=(x+1)^2$

    $⇔x+1-(x+1)^2=0$

    $ ⇔(x+1)(1-(x+1)=0$

    $⇔(x+1)(1-x-1)=0$

    $⇔(x+1)(-x)=0$

    $⇔$ \(\left[ \begin{array}{l}x+1=0\\-x=0\end{array} \right.\) $⇔$ \(\left[ \begin{array}{l}x=-1\\x=0\end{array} \right.\) 

    $\text{Vậy $x∈\{-1;0\}$}$

     

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )