You want the current amplitude through a inductor with an inductance of 4.70 mH (part of the circuitry for a radio receiver) to be 2.40 mA w

Question

You want the current amplitude through a inductor with an inductance of 4.70 mH (part of the circuitry for a radio receiver) to be 2.40 mA when a sinusoidal voltage with an amplitude of 12.0 V is applied across the inductor. What frequency is required?

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Bơ 4 years 2021-08-24T16:22:26+00:00 1 Answers 10 views 0

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  1. dangkhoa
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    2021-08-24T16:24:08+00:00
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    Answer:

    f = 1.69*10^5 Hz

    Explanation:

    In order to calculate the frequency of the sinusoidal voltage, you use the following formula:

    V_L=\omega iL=2\pi f i L         (1)

    V_L: voltage = 12.0V

    i: current  = 2.40mA = 2.40*10^-3 A

    L: inductance = 4.70mH = 4.70*10^-3 H

    f: frequency = ?

    you solve the equation (1) for f and replace the values of the other parameters:

    f=\frac{V_L}{2\pi iL}=\frac{12.0V}{2\pi (2.4*10^{-3}A)(4.70*10^{-3}H)}=1.69*10^5Hz      

    The frequency of the sinusoidal voltage is f

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